# Advanced Array-Based Problem-Solving with LeetCode Examples in Go.

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Array-based problems on platforms like LeetCode often require advanced problem-solving techniques. Let's explore some challenging problems along with their solutions in Go.

## Problem 1: Two Sum

Given an array of integers `nums` and an integer `target`, return indices of the two numbers such that they add up to the `target`.

### Solution:

``````func twoSum(nums []int, target int) []int {
numMap := make(map[int]int)
for i, num := range nums {
complement := target - num
if index, ok := numMap[complement]; ok {
return []int{index, i}
}
numMap[num] = i
}
return nil
}
``````

## Problem 2: Maximum Subarray

Given an integer array `nums`, find the contiguous subarray (containing at least one number) that has the largest sum and return its sum.

### Solution:

``````func maxSubArray(nums []int) int {
maxSum, currentSum := nums[0], nums[0]
for i := 1; i < len(nums); i++ {
currentSum = max(nums[i], currentSum+nums[i])
maxSum = max(maxSum, currentSum)
}
return maxSum
}

func max(a, b int) int {
if a > b {
return a
}
return b
}
``````

## Problem 3: Product of Array Except for Self

Given an integer array `nums`, return an array `output` such that `output[i]` is equal to the product of all the elements of `nums` except `nums[i]`.

### Solution:

``````func productExceptSelf(nums []int) []int {
length := len(nums)
left, right := make([]int, length), make([]int, length)
left[0], right[length-1] = 1, 1

for i := 1; i < length; i++ {
left[i] = left[i-1] * nums[i-1]
right[length-i-1] = right[length-i] * nums[length-i]
}

for i := 0; i < length; i++ {
left[i] *= right[i]
}
return left
}
``````

## Problem 4: Rotate Array

Given an array, rotate the array to the right by `k` steps, where `k` is non-negative.

### Solution:

``````func rotate(nums []int, k int) {
k %= len(nums)
reverse(nums)
reverse(nums[:k])
reverse(nums[k:])
}

func reverse(nums []int) {
left, right := 0, len(nums)-1
for left < right {
nums[left], nums[right] = nums[right], nums[left]
left++
right--
}
}
``````

## Problem 5: Set Matrix Zeroes

Given an `m x n` matrix, if an element is `0`, set its entire row and column to `0`. Do it in place.

### Solution:

``````func setZeroes(matrix [][]int) {
m, n := len(matrix), len(matrix[0])
rows, cols := make(map[int]bool), make(map[int]bool)

for i := 0; i < m; i++ {
for j := 0; j < n; j++ {
if matrix[i][j] == 0 {
rows[i] = true
cols[j] = true
}
}
}

for i := 0; i < m; i++ {
for j := 0; j < n; j++ {
if rows[i] || cols[j] {
matrix[i][j] = 0
}
}
}
}
``````

## Conclusion

LeetCode problems often challenge developers to employ advanced problem-solving skills using arrays in Go. These solutions showcase efficient approaches to tackle diverse array-related problems. Practicing these problems enhances problem-solving abilities and strengthens proficiency in handling arrays in Go, preparing developers to solve a wide array of computational challenges effectively.

I hope this helps, you!!

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